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All Deviations

Comment on ~Copyright-Club[top] [parent]

~the-final-I:iconthe-final-I: Dec 13, 2007, 2:11:00 AM
ok, I googled it.
:|

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E^2= (p^2c^2)+([Δm^2]c^4)
which implies that
E= [mc^2]/[<sq. root>1-(v^2/c^2)]
when p=0 (in eq 1, or in 2 rearranged to 1])
E=mc^2
[as rest mass cannot be attained, p can never=0, so E should, not always be calculated as = mc^2].

Devious Comments

~couleur:iconcouleur: May 17, 2007, 8:46:33 AM
Hi and welcome to DA. :)

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~Copyright-Club:iconCopyright-Club: May 17, 2007, 10:25:36 AM
Thank you! Would you like to join?
~dyasmita:icondyasmita: May 22, 2007, 5:11:30 AM
just in case i'm violated XD

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copyright club: [link] | 12 Kokki Club [link]
~Copyright-Club:iconCopyright-Club: May 22, 2007, 3:54:06 PM
Thanks for joining! Don't forget to put our icon in your journal or our link in your signature. =)
~dyasmita:icondyasmita: May 23, 2007, 8:26:42 AM
uh, sorry I forgot >.<

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me at [link]
copyright club: [link] | 12 Kokki Club [link]
=Larentia-Ariadne:iconLarentia-Ariadne: May 29, 2007, 5:50:37 PM
I do this all the time. :#1:
~Copyright-Club:iconCopyright-Club: May 29, 2007, 9:10:07 PM
:giggle: Good! I like to hear that, theriouthly.
~Arpie:iconArpie: Jun 1, 2007, 5:41:04 PM
I always felt like a snitch for tattling on all the copyright violations. Now I feel better. Thank you guys. :phew:

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